Question

if a car travels 50 m distance in 4s with acceleration of 5m/s^2,then find it's initial speed.

Answer 1

S = ut + 1/2 a t^2
50 = 4u + 1/2 × 5 × 4^2
4u = 10
u = 2.5 m/s
Hence the initial velocity is 2.5 m/s.

Hope this helps..

Answer 2

Hello friend
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Given data
Distance=50m
t=4sec
a=5m/s^2


To find
Initial speed =u= ?

Solution

Wkt

S = ut + 1/2 a t^2
Substitute the given values
50 = 4u + 1/2 × 5 × 4^2
50=4u+5*16/2
50=4u+ 5*8
50=4u+40
50-40=4u
10=4u
U=10/4
U= 2.5 m/s

Were initial velocity = 2.5 m/s

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Hope it's help u