Question

If a car travels 50m distance in 4s with a acceleration of 5m/s square[2] , then what was it's initial speed .

Answer 1

ANSWER

The initial speed of the car is 2.5m/s

GIVEN

• A car travels 50m distance in 4s with an acceleration of 5m/s²

TO FIND

• The initial speed of car

SOLUTION

We have ,

Distance , s = 50m

acceleration , a = 5m/s²

time taken , t = 4s

We know that ,

$\tt \dashrightarrow s = ut + \dfrac{1}{2} at {}^{2} \\ \\ \implies \tt 50 = u \times 4 + \dfrac{1}{2} \times 5 \times 4 {}^{2} \\ \\ \tt \implies 4u + \dfrac{1}{2} \times 5 \times 4 \times 4 = 50 \\ \\ \tt \implies4u + 40 = 50 \\ \\ \tt\implies4u = 50 - 40 \\ \\ \tt\implies4u = 10 \\ \\ \implies \tt u = \dfrac{10}{4} \\ \\ \tt \implies u = \dfrac{5}{2} \\ \\ \tt \implies u = 2.5$

Thus , the initial speed is 2.5m/s

Answer 2

Answer:

Initia Velocity(u) :- 15m/s

Acceleration(a) :- 4m/s2

Time Taken(t) :- 50 Seconds

{ok a formula is there —->>> s = ut + 1/2 at2(it is ‘t’ square)….. now we will write like this and yeah don’t write this}

We Know,

s = ut + 1/2 at2

s = (15*50 + 1/2 *4*50*50)m

s= (750 + 5000)m

s = 5750 m

Therefore distance traveled is 5750 meters.

Explanation: