Question

If a carnot engine works between $127^{o} c$ and $527^{o} c$ , then its efficiency is
(1) 25%
(2) 37.5%
(3) 50%
(4) 75%

Answer 1

Answer:

EFFICIENCY OF CARNOT ENGINE ( ẞ ) = 50%

Explanation:

★ CARNOT ENGINE ★

★ GIVEN ;

» Temperature of Source ( T¹ ) = 527° C ≈ 800 K

» Temperature of Sink ( T² ) = 127° C ≈ 400 K

★ EFFICIENCY OF CARNOT ENGINE

( ẞ ) = ???

_____ [ BY USING FORMULA ] ______

[ $\beta = \: ( \: 1 \: - \: \frac{ {t}^{2} }{ {t}^{1} } \: )$ ]

★ ẞ = [ 1 - 400 / 800 ]

» ẞ = [ 800 - 400 / 800 ]

» ẞ = [ 400 / 800 ] = [ 1 / 2 ]

» » % ẞ ( Efficiency ) = 1 / 2 × 100 =

50 % ««

_______________________________________

ANSWER :- PERCENTAGE EFFICIENCY OF CARNOT ENGINE IS ;

★ ẞ = 50 % ★

Answer 2

Answer:

Efficiency of carnot engine=50%

Explanation:

Given

Temperature of source (T1) = 127°C approx.=400°K

Temperature of sink (T2) approx.=800°K

To calculate efficiency we have formula

$carnot \: engine \: effiency = (1 - \frac{t1}{t2} ) \\ = > (1 - \frac{400}{800} ) \\ = > ( 1- \frac{1}{2} ) \\ = > \frac{1}{2} \\ = > percentage \: = \frac{1}{2} \times 100 \\ = > 50\%$

hence efficiency of carnot engine is 50%