Physics, asked by blackharleyquinn2004, 7 months ago

If a cart with a mass of 12 kg is traveling at 15 m/s and slows down to 11 m/s in 12 seconds. (Intro to GUESS method and acceleration)
What would be the acceleration of the cart?



What would be the net force on the cart during this time?

Answers

Answered by Cynefin
34

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A cart is travelling on a path, and some basic information about its velocity, mass etc is given.

GiveN:

  • Mass of the cart = 12 kg
  • Initial velocity = 15 m/s
  • Final velocity = 11 m/s
  • Time taken = 12 s

To FinD:

  • Accleration of the cart
  • Net force on the cart during this time.

Step-wise-Step Explanation:

We have v, u and t here. So, we can use 1st equation of motion to find the acceleration.

⇒ v = u + at

⇒ 11 = 15 + a(12)

⇒ -4 = 12a

⇒ a = -4 / 12

⇒ a = -1/3 m/s² = - 0.33 m/s²

The accleration of the cart observed during the change of velocity is -0.33 m/

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Now we have got our accleration. Mass is already is provided, So finding the net force applied on the body.

⇒ F = ma

⇒ F = 12 × -1/3 N

⇒ F = -4 N

Hence, the net force on the cart during this time is given by -4 N.

Answered by Anonymous
42

Explanation:

Given : -

  • a cart with a mass of 12 kg

  • traveling at 15 m/s .

  • slows down to 11 m/s in 12 seconds.

To Find : -

  • What would be the acceleration of the cart?

  • What would be the net force on the cart during this time?

Solution : -

we have :

  • What would be the acceleration of the cart?

v = u + at

Substitute all values :

11 = 15 + a × 12

- 12a = 15 - 11

- 12a = 4

a = - 4 / 12

a = 0.33

  • What would be the net force on the cart during this time?

We have :

F = ma

F = 12 × 1/3

F =12 /3

F = 4 N

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