If a cart with a mass of 12 kg is traveling at 15 m/s and slows down to 11 m/s in 12 seconds. (Intro to GUESS method and acceleration)
What would be the acceleration of the cart?
What would be the net force on the cart during this time?
Answers
A cart is travelling on a path, and some basic information about its velocity, mass etc is given.
GiveN:
- Mass of the cart = 12 kg
- Initial velocity = 15 m/s
- Final velocity = 11 m/s
- Time taken = 12 s
To FinD:
- Accleration of the cart
- Net force on the cart during this time.
Step-wise-Step Explanation:
We have v, u and t here. So, we can use 1st equation of motion to find the acceleration.
⇒ v = u + at
⇒ 11 = 15 + a(12)
⇒ -4 = 12a
⇒ a = -4 / 12
⇒ a = -1/3 m/s² = - 0.33 m/s²
The accleration of the cart observed during the change of velocity is -0.33 m/s²
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Now we have got our accleration. Mass is already is provided, So finding the net force applied on the body.
⇒ F = ma
⇒ F = 12 × -1/3 N
⇒ F = -4 N
Hence, the net force on the cart during this time is given by -4 N.
Explanation:
Given : -
- a cart with a mass of 12 kg
- traveling at 15 m/s .
- slows down to 11 m/s in 12 seconds.
To Find : -
- What would be the acceleration of the cart?
- What would be the net force on the cart during this time?
Solution : -
we have :
- What would be the acceleration of the cart?
v = u + at
Substitute all values :
11 = 15 + a × 12
- 12a = 15 - 11
- 12a = 4
a = - 4 / 12
a = 0.33
- What would be the net force on the cart during this time?
We have :
F = ma
F = 12 × 1/3
F =12 /3
F = 4 N