Question

if a Caso - bsin0=C then prove that asin0+bcos0=+√a2+b2-c2​

Answer 1

Answer:

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Answer 2

Answer:

a²cos²∅ + b²sin²∅ - 2a sin∅ b cos∅ + a²cos²∅ + b²sin²∅ + 2a sin∅ … ... If acos theta - bsin theta =c then prove that asin theta ... ( a sin∅ - b cos∅ ) = ±√( a² + b² - c² ) .