If a certain sum of money doubles itself in 7
years 8 months at simple interest, then what will
be the yearly rate of interest (in %)?
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Answer:-
Let the sum (P) be "x".
Given:
Time period = 7 years 8 months
1 year = 12 months
→ 7 years 8 months = 7 * 12 + 8
→ Time Period = 92 months
→ Time Period (T) = 92/12 = 23/3 years.
And,
The sum doubles itself in 23/3 years.
→ Simple Interest = 2*x = 2x
We know that,
Simple Interest = PTR/100
[ R is the rate of interest ]
→ 2x = (x) * (23/3) * R/100
→ 2x = (23x/ 3) * 1/100 * R
→ R = (2x) * (3/23x) * 100
→ R = 26.08 % = 26 % (Approx.)
Therefore, the rate of interest will be 26 % .
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