Question

If a chain link is stressed over its recommended maximum limit, the probability that it will break is 0.7. What is the probability that a chain ten links long will break if it is overloaded?

Answer 1

Answer:

Step-by-step explanation:

You have five numbers. There are 75 possible, so 5/75.

Now, you have four left! So, 4/74.

I am told that only one link in a chain can fail in the real world.

Using the binomial distribution: <SUB>5</SUB>C<SUB>1</SUB>(.7)<SUP>1</SUP>(.3)<SUP>4</SUP>.

P(B or A)=P(A)+P(B)-P(A)P(B)

P(RB or RG or BG)=[10*3 + 10*7 + 3*7]/<SUB>20</SUB>C<SUB>2</SUB>