If a charge of 420C flow through a conducting wire in5 min what is the value of the current?
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Given :-
- Charge (Q) = 420 C
- Time (t) = 5 min
To Find :-
- The value of the current.
Solution :-
First minute convert into second.
⟶ Time = 5 min
⟶ Time = 5 × 60
⟶ Time (t) = 300 seconds
As we know that,
Here,
- I = Electric Currect
- Q = Electric charge
- t = Time
Units,
- I = Ampere, A
- Q = Coulomb, C
- t = seconds, s
[ Substitute the value in the formula ]
⟶ I = 420/300
⟶ I = 42/30
⟶ I = 1.4 A
Therefore,
The value of the current is 1.4 Ampere.
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