if a charge of 50uc in moving with speed of 50m/s parallel to the diraction of magnatic field find acting on charged particle
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Answer:
q=5μF=5×10
−6
C
m=5×10
−12
kg
V=1km/s=10
3
m/s
θ=sin
−1
(0.9), B=5×10
−3
T
We have mv
2
=qv
′
B
r=
qB
mv
′
=
qB
mvsinθ
=
5×10
−6
×5×10
3
5×10
−12
×10
3
×.9
=0.18metre
Hence diameter =36cm
Pitch =
vsinθ
2πr
vcosθ=
0.9
2×3.1416×0.1×
1−0.81
=0.54meter=54cm
The velocity has an x-component along with which no force acts so that the particle, moves with uniform velocity. The velocity has a y-component with which is accelerates with acceleration with verticle component it moves in a circular crosssection. Thus it moves in a helix.
Explanation:
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