Question

if a charge on an electron is 1.6 multiply 10 power minus 19 columns how many electrons present passed through a conductor in one second to constitute 1 ampere current

Answer 1

Hi friend,

Given,

e= 1.6×10^-19

I= 1A
t=1sec

We know that,

Q= ne

(Q=it)

n= it/e

n= 1/1.6×10^-19

n= 6.25×10^18 electrons.

Hope this helped you a little!!!

Answer 2

To solve this problem you should know this fromula => i = nQ/t

n = it / Q
= 1 Ampere × 1 second / (1.6 × 10^-19 Coulomb)
= 6.25 × 10¹⁸
= 6.25 Quintillion electrons

6.25 Quintillion electrons are passed in one second.