If a charge q is placed at the centre of the line joining two equal charges Q such that the system is in equilibrium then the value of q is(a) Q/2(b) –Q/2(c) Q/4(d) –Q/4
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it's answer should be option D
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Answer:
D) -Q/4
Explanation:
An equilibrium is a state in which the opposing forces are balanced. Here, charge q is placed at the center (C) of the line joining two equal charges Q each, at points A and B.
Therefore, let AB=2a
If the net force on each charge will be zero, then the system will be in equilibrium. Let us consider the charge Q at A. Under equilibrium, the total force on one Q
F = kQ²/4a²+kqQ/a²
For the system to be in equilibrium F = 0
Thus, kQ²/4a²+kqQ/a²=0
q = −Q/4.
Hence, the system is in equilibrium then the value of q is -Q/4
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