Question

If a charged q is placed at the center of the line joining two equal charge q such that the system in equilibrium then value of q is​

Answer 1

Answer:

-q/4

Explanation:

At equilibrium, net force will be zero, hence

∴ 1/4πε0 × Qq/(r/2)2 + 1/4πε0 × Q2/r2 =0

4q=−Q or q= −Q/4.