Question

If a child wants to make a closed match box of same dimensions with thin card board, what is the minimum area of card board required to make it? *
1 point
60.5 sq cm
26.25 sq cm
30.25 sq cm
none of the above

Answer 1

Answer:

व्हॉल्यूम

ऑब्जेक्ट सॉलिड बॉडीने व्यापलेली जागा विशिष्ट ऑब्जेक्टचे घन शरीराचे प्रमाण नेहमी असते असे म्हणतात क्यूबिक युनिटमध्ये मोजले जाते.

दिले:

मॅचबॉक्सचे परिमाण = 4 c मी x 2.5 कमी x =

1.5कमी

1=4cमी, ब= 2.5 कमी &h= 1.5 कमी

क्यूबॉइडचे परिमाण = (1 × b × h)

=

Volume of one matchbox= Volume of cuboid

Volume of one matchbox = 4 x 2.5 × 1.5 =

15cm

Volume of a packet containing 12 such boxes = 12x volume of one match box

(12 × 15) cm 3 = 180cm3

Hence, the volume of a packet containing 12

hope this is help you ☺