Question

If a chord of a circle of radius 28 cm makes an angle of 90 ° at the centre, then the area of the major segment is
(a)392 cm²
(b)1456 cm²
(c)1848 cm²
(d)2240 cm²

Answer 1

Answer:

Area of the major segment is 2240 cm²

Among the given options option (d) 2240 cm² is the correct answer.

Step-by-step explanation:

Given :

Radius of a circle,r = 28 cm  

Angle at the centre of a circle, θ = 90°

Area of the major segment ,A = Area of circle - Area of minor segment

A = πr² - {πθ/360 - sin θ /2 cos θ/2 }r²

A = π × 28² - {90°π/360° - sin 90°/2 cos 90°/2 }× 28²

A = 784π -  {π/4  - sin 45°cos 45°} × 784

A = 784π - {π/4  - 1/√2 × 1/√2} × 784

A = 784π - {π/4  - 1/2 } × 784

A = 784π -  {784π/4 - 784/2}

A = 784π - {784 × 22/7 × 1/4 - 392}

A = 784π - (28 × 22 - 392)

A = 784 × 22/7 - (616 - 392)

A = 112 × 22 -  (224)

A = 2464 - 224

A = 2240 cm²

Area of the major segment = 2240 cm²

Hence, Area of the major segment is 2240 cm²

HOPE THIS ANSWER WILL HELP YOU….

Answer 2

Answer.....

Hey mate

The area of major segment is 2240cm^2

hope it's help uh