if a chord of a circle of radius 28cm makes an angle of 90degrees at the centre then the area of the major segment is
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Here given radius =28cm
Required area = area of the major sector - area of the right triangle
=(x/360×pi×r^2)-r^/2
=(270/360×22/7×28×28)-(28×28)/2
=(28×28)/2[33/7-1]
=(28×14)[(33-7)/7]
=(28×14×26)/7
=28×2×26
=1456sqcm
Required area = area of the major sector - area of the right triangle
=(x/360×pi×r^2)-r^/2
=(270/360×22/7×28×28)-(28×28)/2
=(28×28)/2[33/7-1]
=(28×14)[(33-7)/7]
=(28×14×26)/7
=28×2×26
=1456sqcm
pepy:
thanks
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