if a circle cuts a parabola at the points P, Q, R, S show that PQ and RS are equally inclined to the axes.
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the circle is of the form: x
2
+y
2
+2gx+2fy+c=0
the parabola is of the form: y
2
=4ax
as the circle and parabola intersect at four points and any point on the parabola is of the form (at
2
,2at)
let the point (at
2
,2at) lies on the circle and we get
a
2
t
4
+t
2
(4a
2
+2ag)+4aft+c=0
since sum of the roots is equal to zero
i.e. t
1
+t
2
+t
3
+t
4
=0
the sum of the ordinates of the points
the slope of two pair of points, let's say points
similarly, the slope of other two pair of points
as a result, we get 1
= 0 , which was proved earlier.
thus, the lines are equally inclined to the axis.
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0
Answer:
thanks for free points
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