If a circle passes through the point (0,0),(0,a)(0,b) then the coordinates of its centre is
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Answer:
(a/2,b/2)
Step-by-step explanation:
Equation of circle, given point (0,0)→c=0
Equation of circle, given point (a,0)→a²+2ga+c=0→a(a+2g)=0⇒g=−a/2
Equation of circle, given point (0,b)→b(b+2f)=0⇒f=−b/2
Center of circle =(−g,−f)=(a/2,b/2)
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