if a circle passing through origin has intercepts on on x axis and y axis are 3 and 4 respectively the find the equation of the circle
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x^2 + y^2 + 2gx +2fy+c= 0
Radius = √[(a/2)² + (b/2)²].
( x-a/2) ² + ( y-b/2)² = (a/2)² +(b/2)²
Anonymous:
okay I will give
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