Math, asked by Epicitup, 1 year ago

if a circle passing through origin has intercepts on on x axis and y axis are 3 and 4 respectively the find the equation of the circle ​

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Answered by Anonymous
3

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x^2 + y^2 + 2gx +2fy+c= 0

Radius = √[(a/2)² + (b/2)²].

( x-a/2) ² + ( y-b/2)² = (a/2)² +(b/2)²


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