if a circle pound has outer circumference 44m and inner path 2m wide find the area of path and area of inner circle
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Answered by
1
hey mate!
here is your answer:
Step By Step Explanation:
Circumference of outer circle =2×pie×radius
44=2×22/7×radius
44×7/22×2=radius
7m=radius
area of outer circle= pie×radius ^2
area=22/7×7×7
area=154m^2
radius of inner circle=radius of outer circle-widthof path= 7-2=5m
area of inner circle=pie×radius^2
area=22/7×5×5
area=550/7m^2
now, area of path=area of outer circle -area of
inner circle
area of path=154-550/7=1078-550/7=528/7m^2
hope it helped ^_^
here is your answer:
Step By Step Explanation:
Circumference of outer circle =2×pie×radius
44=2×22/7×radius
44×7/22×2=radius
7m=radius
area of outer circle= pie×radius ^2
area=22/7×7×7
area=154m^2
radius of inner circle=radius of outer circle-widthof path= 7-2=5m
area of inner circle=pie×radius^2
area=22/7×5×5
area=550/7m^2
now, area of path=area of outer circle -area of
inner circle
area of path=154-550/7=1078-550/7=528/7m^2
hope it helped ^_^
Answered by
0
78.5m² = Area of the inner circle
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