If a circle touches all the four sides of
a quadritateral ABCD at points P,Q,R, s
then show that AB+CD = BC+AD
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Step-by-step explanation:
Lengths of the tangents from an external point are equal.
AP = AS, BP = BQ, CR = CQ and DR = DS
AB + CD = (AP + BP) + (CR + DR)
= AS + BQ + CQ + DS
= (AS + DS) + (BQ + CQ)
= AD + BC
Hence AB + CD = AD + BC.
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Answer:
please give me diagram ......then I can judge
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