Question

If a circle touches all the four sides of
a quadritateral ABCD at points P,Q,R, s
then show that AB+CD = BC+AD​

Answer 1

Step-by-step explanation:

Lengths of the tangents from an external point are equal.

AP = AS, BP = BQ, CR = CQ and DR = DS

AB + CD = (AP + BP) + (CR + DR)

= AS + BQ + CQ + DS

= (AS + DS) + (BQ + CQ)

= AD + BC

Hence AB + CD = AD + BC.

Answer 2

Answer:

please give me diagram ......then I can judge