If a coin is tossed 6 times, then the probability of getting exactly 1 head is ..
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Total number of possible outcomes = 2 (That is, head or tail)
P(head) = 1/2
P(tail) = 1/2
P(exactly 1 head in 6 throws) = 6 [ P(head)¹ x P(Tail)⁵ ]
P(exactly 1 head in 6 throws) = 6 [ (1/2) x (1/2)⁵ ]
P(exactly 1 head in 6 throws) = 6 [ 1/64 ]
P(exactly 1 head in 6 throws) = 3/32
Answer: The probability of getting exactly 1 head in 6 throws in 3/32
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