Question

if a coin is tossed twice what is the out come of the event of getting at least 1 tail ​

Answer 1

$\huge{ \mathfrak{\purple{Answer}}}$

3/4

$\huge{ \mathfrak{\purple{Explanation}}}$

Given

A Coin is tossed Twice

To find

The out come of the event of getting at least 1 tail

S ={ HH, HT, TT, TH}

n (S) = 4

Out come of Atleast One tail (A)= {HT, TT, TH}

n (A) = 3

p (A) = n(A) / n(S)

= 3/4

So, The probablity of out come of the event of getting at least 1 tail is 3/4

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