Question

If a coin is tossed upwards from the ground with a velocity of 9.8m/sec then it rises to a height

Answer 1

Answer:

v^2-u^2=2as

v=0  u=9.8m/s

a= -g.     {g=9.8m/s}

since it is against the gravity let us take it as -g=-9.8

by substituting the values

0-(9.8)^2=2x-9.8xs

s=4.9m

Explanation:

why v=0...if it reaches its maximum height 's' it will havw its final velocity 'v' 0..:)