Question

if a complex number 2is purely imaginary then conjugate of 2 is,?​

Answer 1

Answer:

If a polynomial has two conjugate roots, let x±iy, it must be a multiple of

(z−x−iy)(z−x+iy)=z2−2xz+x2+y2.

Notice that all coefficients are real. In fact, the roots of a polynomial of real coefficients are either reals or pairs of complex conjugates. Such a polynomial can always be factored as the product of quadratic and linear factors with real coefficients.

Answer 2

Answer:

Let w = z - 2z + 2 Since, w is purely imagina

Step-by-step explanation:

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