Question

If a compound has a molar mass of 180 g/mol and its empirical formula is CH2O, what is its molecular formula? CH2O C2H4O2 C6H12O6 C12H22O11

Answer 1

Answer:- Molecular formula is $C_6H_1_2O_6$

Solution:- Molecular formula as n number of empirical formula units where n has values like 1,2,3 and so on.

n is calculated on dividing the molar mass by the empirical formula mass.

Molar mass is given as 180 and the empirical formula mass is calculated from given empirical formula, $CH_2O$ .

empirical formula mass = 12+2(1)+16 = 30

where, 12 is the atomic mass of C, 1 is the atomic mass of H and 16 is the atomic mass of O(round off values has been used here)

n = $\frac{180}{30}$ = 6

Number of empirical formula units is 6 it means the molecular formula has six empirical formula units. So, we do six times of each element present in given empirical formula.

Hence, the molecular formula is  $C_6H_1_2O_6$ .

Answer 2

Answer: Answer:- Molecular formula is C_6H_1_2O_6

Explanation: