Computer Science, asked by tekchand1821, 1 year ago

If a computer has eight-byte addressability and needs three bits to access a location in memory, what is the total size of memory in bytes

Answers

Answered by 2323ishan
6
8byte addressability: 8bytes can be stored in each memory location. 3bits to access: so 8 memory locations ( 2^3) total size = 8 * 8bytes( each memory location contains) = 64 bytes any queries 
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