Question

If a concave mirror has a focal length of 10 cm fin the two positions where an object can be placed to give, in each case, an image twice the height of the object​

Answer 1

Answer:

Explanation:

U = OBJECT DISTANCE    V = IMAGE DISTANCE       M = MAGNIFICATION

hi = image height    ho = object height

f = -10cm

hi = 2ho

1/f = 1/v + 1/u

1/-10 = 1/v + 1/u

1/v = -1/u - 1/10

1/v = -(10 + u/10u)

-1/v = 10 + u / 10u

-v = 10u/10 + u

M = hi /ho

= 2ho/ho

= 2

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Answer 2

Answer:

Between C and F

Explanation: