Physics, asked by bigben1110, 10 months ago

If a concave mirror of focal length 18 cm and magnification of 2 forms a real image of an object on its principal axis. Find the position of image​

Answers

Answered by Anonymous
30

Answer:

hope it helps you see the attachment for further information

Attachments:
Answered by muscardinus
15

The image will be formed at a distance of 54 cm.

Explanation:

It is given that,

Focal length of the concave mirror, f = -18 cm (focal length of concave mirror is negative)

Magnification of the mirror, m = -2 (negative when the image is real)

The magnification of the mirror is given by:

m=\dfrac{-v}{u}

-2=\dfrac{-v}{u}

v=2u

Using mirror's formula to find the position of image. It is given by :

\dfrac{1}{v}+\dfrac{1}{u}=\dfrac{1}{f}

v and u are image and object distance

\dfrac{1}{2u}+\dfrac{1}{u}=\dfrac{1}{-18}

u = -27 cm

Image distance is,

v=2u

v=2(-27)

v = -54 cm

So, the image will be formed at a distance of 54 cm. hence, this is the required solution.

Learn more,

Mirror's formula

https://brainly.in/question/14163016

Similar questions