Question

If a conductor 0.2m long moves with a velocity of 0.3m/s in a magnetic field of 5T, calculate the emf induced if magnetic field, velocity and length of conductor are mutually perpendicular to each other.​

Answer 1

Given :

Length of conductor = 0.2m

Velocity = 0.3m/s

Magnitude of magnitude field = 5$\sf{T}$

To Find :

We have to find induced εmf in conductor$.$

SoluTion :

The εmf induced in a conductor of length l moving with velocity v perpendicular to field B is given B is given by

• ε = B × l × v

⇒ ε = B × l × v

⇒ ε = 5 × 0.2 × 0.3

⇒ ε = 0.3 V

Answer 2

Explanation:

Given :

Length of conductor = 0.2m

Velocity = 0.3m/s

Magnitude of magnitude field = 5\sf{T}T

To Find :

We have to find induced εmf in conductor..

SoluTion :

The εmf induced in a conductor of length l moving with velocity v perpendicular to field B is given B is given by

ε = B × l × v

⇒ ε = B × l × v

⇒ ε = 5 × 0.2 × 0.3

⇒ ε = 0.3 V