Question

if a conductor carrying a current of 200 ma find the amount of charge that will pass through the cross section of the conductor in 30s how many electrons will flow in this time interval is charge on an electron is 1.6 into 10 to the power minus 19 c

Answer 1

hey friend
here's your answer
Q=It; hence Q=(200×10^-3)×30=12C
no.of electrons=12/6×10^-19=2×10^19
hope it helps you