Question

if a cone of a rohmbus is 60°. then,The ratio of the length of the edge is ??​

Answer 1

EXPLANATION-: Suppose given rhombus is ABCD , with each side = 10 cm, smaller diagonal is BD & longer diagonal is AC , with point of intersection O.

Suppose given rhombus is ABCD , with each side = 10 cm, smaller diagonal is BD & longer diagonal is AC , with point of intersection O.TO FIND: AC = ?

Suppose given rhombus is ABCD , with each side = 10 cm, smaller diagonal is BD & longer diagonal is AC , with point of intersection O.TO FIND: AC = ?< A = 60°

Suppose given rhombus is ABCD , with each side = 10 cm, smaller diagonal is BD & longer diagonal is AC , with point of intersection O.TO FIND: AC = ?< A = 60°=> triangle ABD is an equilateral triangle. as AB = AD hence base angles will be equal. & each will be of 60°

Suppose given rhombus is ABCD , with each side = 10 cm, smaller diagonal is BD & longer diagonal is AC , with point of intersection O.TO FIND: AC = ?< A = 60°=> triangle ABD is an equilateral triangle. as AB = AD hence base angles will be equal. & each will be of 60°Hence smaller diagonal BD = 10 cm => BO = 10/2 = 5 cm

Suppose given rhombus is ABCD , with each side = 10 cm, smaller diagonal is BD & longer diagonal is AC , with point of intersection O.TO FIND: AC = ?< A = 60°=> triangle ABD is an equilateral triangle. as AB = AD hence base angles will be equal. & each will be of 60°Hence smaller diagonal BD = 10 cm => BO = 10/2 = 5 cmAs, diagonals of a rhombus, bisect each other at right angles.

Suppose given rhombus is ABCD , with each side = 10 cm, smaller diagonal is BD & longer diagonal is AC , with point of intersection O.TO FIND: AC = ?< A = 60°=> triangle ABD is an equilateral triangle. as AB = AD hence base angles will be equal. & each will be of 60°Hence smaller diagonal BD = 10 cm => BO = 10/2 = 5 cmAs, diagonals of a rhombus, bisect each other at right angles.=> tri AOB is a right triangle with hypotenuse AB.

Suppose given rhombus is ABCD , with each side = 10 cm, smaller diagonal is BD & longer diagonal is AC , with point of intersection O.TO FIND: AC = ?< A = 60°=> triangle ABD is an equilateral triangle. as AB = AD hence base angles will be equal. & each will be of 60°Hence smaller diagonal BD = 10 cm => BO = 10/2 = 5 cmAs, diagonals of a rhombus, bisect each other at right angles.=> tri AOB is a right triangle with hypotenuse AB.AB² = BO² + AO²

Suppose given rhombus is ABCD , with each side = 10 cm, smaller diagonal is BD & longer diagonal is AC , with point of intersection O.TO FIND: AC = ?< A = 60°=> triangle ABD is an equilateral triangle. as AB = AD hence base angles will be equal. & each will be of 60°Hence smaller diagonal BD = 10 cm => BO = 10/2 = 5 cmAs, diagonals of a rhombus, bisect each other at right angles.=> tri AOB is a right triangle with hypotenuse AB.AB² = BO² + AO²=> 10² = 5² + AO²

Suppose given rhombus is ABCD , with each side = 10 cm, smaller diagonal is BD & longer diagonal is AC , with point of intersection O.TO FIND: AC = ?< A = 60°=> triangle ABD is an equilateral triangle. as AB = AD hence base angles will be equal. & each will be of 60°Hence smaller diagonal BD = 10 cm => BO = 10/2 = 5 cmAs, diagonals of a rhombus, bisect each other at right angles.=> tri AOB is a right triangle with hypotenuse AB.AB² = BO² + AO²=> 10² = 5² + AO²=> AO = √(100 - 25)

Suppose given rhombus is ABCD , with each side = 10 cm, smaller diagonal is BD & longer diagonal is AC , with point of intersection O.TO FIND: AC = ?< A = 60°=> triangle ABD is an equilateral triangle. as AB = AD hence base angles will be equal. & each will be of 60°Hence smaller diagonal BD = 10 cm => BO = 10/2 = 5 cmAs, diagonals of a rhombus, bisect each other at right angles.=> tri AOB is a right triangle with hypotenuse AB.AB² = BO² + AO²=> 10² = 5² + AO²=> AO = √(100 - 25)=> AO = √75 = 5√3 cm

Suppose given rhombus is ABCD , with each side = 10 cm, smaller diagonal is BD & longer diagonal is AC , with point of intersection O.TO FIND: AC = ?< A = 60°=> triangle ABD is an equilateral triangle. as AB = AD hence base angles will be equal. & each will be of 60°Hence smaller diagonal BD = 10 cm => BO = 10/2 = 5 cmAs, diagonals of a rhombus, bisect each other at right angles.=> tri AOB is a right triangle with hypotenuse AB.AB² = BO² + AO²=> 10² = 5² + AO²=> AO = √(100 - 25)=> AO = √75 = 5√3 cm=> 2AO = 10√3 cm

Suppose given rhombus is ABCD , with each side = 10 cm, smaller diagonal is BD & longer diagonal is AC , with point of intersection O.TO FIND: AC = ?< A = 60°=> triangle ABD is an equilateral triangle. as AB = AD hence base angles will be equal. & each will be of 60°Hence smaller diagonal BD = 10 cm => BO = 10/2 = 5 cmAs, diagonals of a rhombus, bisect each other at right angles.=> tri AOB is a right triangle with hypotenuse AB.AB² = BO² + AO²=> 10² = 5² + AO²=> AO = √(100 - 25)=> AO = √75 = 5√3 cm=> 2AO = 10√3 cm=> AC = 10√3 cm

Hope you understood