Question

if a cone of length l and radius R is placed in uniform electric field the flux passing through the plane​

Answer 1

Answer:

Let the Gaussian cube of side s such that the charge is placed at its centre.

Thus electric flux passing through the cube      ϕcube=ϵoQ

As the charge is placed symmetric about all the 6 faces of cube, thus flux passing through one face is equal to the one-sixth of the total flux passing through the entire cube.

∴ Flux passing through the square        ϕ1=6ϕcube=6ϵoQ

hope like it

Answer 2

Answer:

E(πR^2)

Explanation:

Ø=E.ds

And since the projection of come on 2-D surface gives circle, when you flatten it

Area is πR^2

And assuming that Electric field is E, we get ø=E(6πR^2)

Hope this answer helped