Question

If a constant force acts on a body initially at
rest, the distance moved by the body in time 't' is
proportional to ? (With EXPLANATION)​

Answer 1

Answer:

If the body is initially at rest then distance is directly proportional to the acceleration...

Explanation:

acc to formula

x = ut + ½ a t²

Answer 2

Answer:

$s \: \alpha \: {t}^{2}$

Explanation:

$f \: = \: ma = > \: constant \\ \: \: \: \: \: \: \: \: a = \: constant$

given u = 0

for uniform acceleration,

$s \: = \: ut + \frac{1}{2} {at}^{2}$

then

$s \: = \: \frac{1}{2} {at}^{2}$

ie,

$s \: \alpha \: {t}^{2}$

hope this help you