If a copper rod carries a direct current, the magnetic field associated with current will be
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The physical answer is that the magnetic field B inside the tube is zero due to the symmetry of the situation. You can think of the tube as a series of thin wires arranged in a circle.
For each of these wires, which generates a constant magnetic field both inside and outside the “tube,” there is another wire—the one located opposite to the first on a diameter of the tube—which generates a field that exactly cancels the field from the first wire at every point within the tube. (Try visualizing this with the right-hand rule if you don’t believe me.)
The world outside the tube does not have this nice symmetry, so the field outside the tube is nonzero.
×_×_×_×_×_×_×_×_×
For each of these wires, which generates a constant magnetic field both inside and outside the “tube,” there is another wire—the one located opposite to the first on a diameter of the tube—which generates a field that exactly cancels the field from the first wire at every point within the tube. (Try visualizing this with the right-hand rule if you don’t believe me.)
The world outside the tube does not have this nice symmetry, so the field outside the tube is nonzero.
×_×_×_×_×_×_×_×_×
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