if a copper wire of resistivity 1.6× 10*-8 ohm meter has cross section area of 10.3 ×10*-4 cm*2 calcute the length of wire required to make a 20 ohm resistance
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Answer:
Given,
R=10Ω
A=10×10
−8
m
2
ρ=1.6×10
−8
Ω/m
We know that,
R=ρ
A
l
l=
ρ
RA
=
1.6×10
−8
10×10×10
−8
l=62.5m
The length of wire copper wire is 62.5m
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