Question

If a cos 0 + b sin 0 = 3 and a sin 0 - b cos
0 = 4, then the value of a2 + b2 is :​

Answer 1

a cos 0 + b sin 0 = 3

Since cos 0 is 0 and sin 0 is 1 substitute in the above equation

Then, a(0)+ b(1) = 3

b= 3

And..

a sin 0 - 6 cos 0 = 4

a= 4

So, here 'a' value is 4 and 'b' value is 3

The given equation is 2a+ 2b

substitute a and b values in 2a + 2b

Then, 2 (4) + 2(3)

= 8+6

=14