Question

If a cos 0 – b sin 0 = c, then show that a sin 0 + b cos 0 =+√a^2+b^2-c^2​

Answer 1

Answer:

so simple just put the values nicely

Step-by-step explanation:

ok

Answer 2

Step-by-step explanation:

acosθ - bsinθ=c

Squaring both sides

a²cos²θ+b²sin²θ − 2absinθcosθ = c²

⇒  a²(1 - sin²θ)+b²(1 - cos²θ) - 2absinθ

⇒ a² - a²sin²θ + b² - b²cos²θ - 2absinθ cosθ=c²

⇒ asin²θ + b²cos²θ + 2absinθcosθ = a² + b² - c²

⇒ (asinθ + bcosθ)² = a² + b² - c²

⇒ a sinθ + bcosθ = a² + b² - c²

Hope it helps!