Question

If a cos 0 = x and b cot 0 = y, show that
$a ^{2}\div x ^{2} - b {}^{2} \div y {}^{2} = 1$
​

Answer 1

Answer:

a cos A = x (or) $\frac{a}{x}$ = $\frac{1}{cos A}$ (or)  $\frac{a}{x} = sec A$

b cot A = y (or) $\frac{b}{y}$ = $\frac{1}{cot A}$  (or)  $\frac{b}{y} = tan A$

Therefore,  

​$\frac{a^{2} }{x^{2} } - \frac{b^{2} }{y^{2}} = 1$

$[\frac{a}{x}] ^{2} - [\frac{b}{y}] ^{2} = 1$

$sec^{2} A - tan^{2} A = 1$

[LHS = RHS]

HENCE PROVED

Hope it helped...

Do mark it as 'Brainliest'