Question

if a=cos^2theta-sin^2theta
b=costheta-sintheta
prove that a^2=b^2(2-b^2)​

Answer 1

Step-by-step explanation:

a=cos^2Q-sin^2Q

b=cosQ-sinQ

a^2=b^2(2-b^2)

(cos^2Q-sin^2Q)^2= (cosQ-sinQ)2[2-(cosQ-sinQ)2]