Question

If a cos theta = b sin theta, and a cos^ 3 theta + b sin^3 theta = sin theta cos theta then a^2 + b ^2 =​

Answer 1

Answer:

1

Step-by-step explanation:

let theta=@

Now

a cos^3@+bsin^3@[email protected]@

• acos@(cos^2@) + bsin@(sin^2@)= [email protected]@

• given,acos@=bsin@--------->1

take acos@ common

acos@[cos^2@+sin^2@][email protected]@

acos@[email protected]@ [cos^2@+sin^2@=1]

• a=sin@ put in eq 1
• then we get
• b=cos@

NOW,

a^2+b^2=sin^2@+cos^2@ = 1