if a cos theta - b sin theta =c prove that asin theta + b cos theta =√a^2+b^2-c^2
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Step-by-step explanation:
If asinθ+bcosθ=c, then prove that acosθ−bsinθ=a2+b2−c2 ... ( √(a²+b²-c²) )² = ( a sin θ - b cos θ )² ... (a) tanx+secx=2cosx.
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