If a cos tita + b sin 0tiya = p, a sin tita - b cos tita = q then
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Answer:
answer:
tanθ=
b
a
=
cosθ
sinθ
asinθ+bcosθ
asinθ−bcosθ
a×a+b×b
a×a−b×b
a
2
+b
2
a
2
−b
2
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