If a×cos x + b × cos x = c, then the value of (a × sin x – b²cos x)² is
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A
2∣b∣
1
d
2
−a
2
asinx+bcos(x+θ)+bcos(x−θ)=d
⇒asinx+2b⋅cosx⋅cosθ=d
⇒∣d∣≤
a
2
+4b
2
cos
2
θ
⇒
4b
2
d
2
−a
2
≤cos
2
θ
⇒∣cosθ∣≥
2∣b∣
d
2
−a
2
.
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