if A=cos2theta+ sin4theta for all value of theta , where A belongs [a,b] , then 4a+b is
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⭐Required answer:-
A=cos 2 θ+sin 4θ
A=cos 2 θ+sin 2 θsin 2 θ≤cos 2 θ+sin 2 θ
A=cos 2 θ+sin 2 θsin 2 θ≤1 (sin 2 θ+cos 2 θ=1). ----(1)
or A=cos 2θ+sin 4 θ
A=(1−sin 2 θ)+sin 4 θ
A=(sin 2 θ) 2 +( 21 )
2 −2× 21 ×sin 2θ+(1− 41 )
A=(sin 2 θ− 21 ) 2 + 43 ≥ 43
----------(2)
From equation 1 and 2,
43 ≤A≤1
so option B will be the correct answer
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