If A(cosa, sin a),B(sin a, -cosa), C(1,2) are the vertices of a AABC, then as a varies the locus of its
centroid.
(1) 3(x² + y²) - 2x - 4y+1=0
(2) None of these
(3) x + y - 2x - 4y +3 = 0
(4) x² + y - 2x - 4y+1=0
Answers
Answered by
0
Answer:
C is the correct answer
Step-by-step explanation:
its halp you
Similar questions