Question

If A(cosa, sina), B(sina, - cosa), C (1,2) are the vertices of a triangle ABC then the locus of its centroid is​

Answer 1

Answer:

locus of centroid is { ( cos a + sin a + 1 )/3 ,(sin a - cos a + 2)/3}

Step-by-step explanation:

Centroid define the centre of gravity of any object which is in 2D or 3D.

centroid of triangle is given by the formula

G=[(x1 + x2 +x3) / 3 ,(y1 +y2 +y3)/3]

therefore centroid or locus of centroid of above

question is

G=[(cos a + sin a + 1) /3 ,( sin a - cos a + 2)/3]

Answer