If a cosecΦ=b and a cotΦ=c,prove that a²+c²=b²
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Answered by
3
Step-by-step explanation:
a cosecΦ= b, a cosecΦ=b/a
a cotΦ= c, cotΦ= c/a
Using,
cosec²Φ - cot²Φ= 1
=>b²/a² - c²/a² = 1
=> (b²-c²)/a² = 1
=> b² - c² = a²
=> b² = a² + c² (Hence proved)
Answered by
2
The answer is attached.
It has used the identity cosec theta = cot theta + 1
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