Question

if a coso+b sino=4 and a sino-b coso=3,then a^2+b^2 is​

Answer 1

. ( quad a cos theta+b sin theta=-3 rightarrow 0 ) Nquaing [ a^{2} cos theta+b^{2} sin 2 theta+2 a b cdot sin theta cdot cos theta=9 ] ( a sin theta+b cos theta=4 quad longrightarrow(2 ) Daving, ( a^{2} cos 2 theta+b^{2} cos 1 theta-2 a b sin theta cdot cos theta=frac{16}{-} ) (1) Adding (3) ( operatorname{and}(4), quadleft[cos ^{2} theta+sin ^{2} theta=1right] ) [ Rightarrow quad a^{2}+b^{2}=9+16=25 ]

answer is 25

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