If a cot θ = 1 and b cos θ = 1, find b^2-a^2
please answer I will mark first answer brainliest
Answers
Answered by
1
Step-by-step explanation:
acot∅=1
a=1/cot∅
a=tan∅
bcos∅=1
b=1/cos∅
b=sec∅
to find:b²-a²
=sec²∅-tan²∅
=1 is the correct answer..
Answered by
4
Answer:
please last time mark me as brainliest plz
Similar questions