Question

If a cube of edge 20 cm melted and recast the cube
of 5 cm How many such cubes can be recast?​

Answer 1

Answer:

64 such cubes can be recast.

Step-by-step explanation:

Volume of big cube = 20³ = 8000

Volume of a small cube = 5³ = 125

$\frac{8000}{125} = \frac{320}{5} = 64$

Answer 2

Volume of cube = side³

VOLUME OF BIG CUBE = Side³

= 20³

= 8000cm³

VOLUME OF SMALL CUBE = Side³

= 5³

= 125cm³

No. Of Cubes can be casted =

Volume of Big cube / Volume of small cube

8000/125

= 64 cubes can be recast

Thanks.